Question

10*{81^2:(3^2)^4+2*[(2^2*3)^15÷(2^29*3^15)+1]}

Answer 1

$\left(10\cdot \:81^2\div \left(3^2\right)^4\right)+2\left[\left(\left(2^2\cdot \:3\right)^{15}\div \left(2^{29}\cdot \:3^{15}\right)\right)+1\right] = \left(10\cdot \:81^2\div \:9^4\right)+2\cdot \:3=\left(10\cdot \:81^2\div \:9^4\right)+6=16$