Question

10+{81^2:(3^2)^4+2×[(2^2×3)^15:(2^29×3^15)+1]}
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Answer 1

Răspuns:

81^2=(3⁴)²=3⁸(3 la a8 a)

(3²)⁴=3⁸

==> 81^2:(3^2)^4=3⁸:3⁸=3⁸-⁸=3⁰=1

[(3*2²)¹⁵:(2²⁹*3¹⁵)]=[(3¹⁵*2³⁰):(2²⁹*3¹⁵)]=(3¹⁵−¹⁵*2³⁰−²⁹)=(3⁰*2¹)=1*2=2

==>10+{81^2:(3^2)^4+2×[(2^2×3)^15:(2^29×3^15)+1]}=

=10+{3⁸:3⁸+[(3¹⁵*2³⁰):(2²⁹*3¹⁵)+1]=10+[1+(2+1)]=10+4=14

Explicație pas cu pas: