Question

10×{81² : (3²)⁴+2×[(2²×3)^15 : (2^29 × 3^15)+1]}

Answer 1

$10*{81^2 : (3^2)^4+2*[(2^2*3) ^{15} : (2 x^{29} * 3 x^{15} )+1]} =$$10{( 3^{4})^2:3^8+2[ \frac{(2^2*3) ^{15} }{2 x^{29}*3 ^{15} }+1]}=10(3^8:3^8+2[ \frac{2 ^{30}*3 ^{15} }{2 ^{29}*3 ^{15} } +1])=$10(1+2[2+1])=10(1+2*3)=10(1+6)=10*7=70