Question

10×{81la puterea2 :(3la puterea a 2)la puterea 4+2×[(2la puterea2×3)la puterea15:(2la puterea29×3la puterea15)+1]}​

Answer 1

10 x {81^2 : (3^2)^4 + 2 x[(2^2 x 3)^15 : (2^29 x 3^15) + 1]} = 10 x{(3^4)^2 : 3^8 + 2 x [(2^2)^15 x 3^15 : (2^29 x 3^15) + 1]} = 10 x {3^8 : 3^8 + 2 x [(2^30 x 3^15) :  (2^29 x 3^15) + 1]} = 10 x [1 + 2 x (2 + 1)] = 10 x (1 + 2 x 3) = 10 x 7 = 70