Matematică, întrebare adresată de jotarojjoestar, 8 ani în urmă

[(-10/9):(+35/27)+(-4/21):(-2/3)]:(-4/14)​

Răspunsuri la întrebare

Răspuns de pav38
9

Răspuns: 2

Explicație pas cu pas:

\bf\Big[\Big(-\dfrac{10}{9} \Big):\Big(\dfrac{35}{27} \Big)+\Big(-\dfrac{4}{21} \Big):\Big(-\dfrac{2}{3} \Big)\Big]:\Big(-\dfrac{4}{14} \Big)=

\bf\Big[\Big(-\dfrac{10}{9}:\dfrac{35}{27} \Big)+\Big(-\dfrac{4}{21} \Big):\Big(-\dfrac{2}{3} \Big)\Big]:\Big(-\dfrac{\not4}{\not14} \Big)=

\bf\Big(-\dfrac{10}{9}\cdot\dfrac{27}{35} +\dfrac{4}{21} :\dfrac{2}{3} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(-\dfrac{\not10}{\not9}\cdot\dfrac{\not27}{\not35} +\dfrac{4}{21} \cdot\dfrac{3}{2} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(-\dfrac{2}{1}\cdot\dfrac{3}{7} +\dfrac{\not4}{\not21} \cdot\dfrac{\not3}{\not2} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(-\dfrac{6}{7}+\dfrac{2}{7} \cdot\dfrac{1}{1} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(-\dfrac{6}{7}+\dfrac{2}{7} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(\dfrac{-6+2}{7} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\Big(-\dfrac{4}{7} \Big):\Big(-\dfrac{2}{7} \Big)=

\bf\dfrac{4}{7}:\dfrac{2}{7} =

\bf\dfrac{4}{7}\cdot\dfrac{7}{2} =

\bf\dfrac{\not4}{\not7}\cdot\dfrac{\not7}{\not2} =

\bf\dfrac{2}{1}\cdot\dfrac{1}{1} =

\boxed{\bf 2}

==pav38==

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