Question

10. Calculaţi, aplicând regulile de calcul cu puteri: b).
[9/5*(9/5)^12]^3:(9/5)^10
va roog​

Answer 1

Răspuns:

Explicație pas cu pas:

$\bigg[\dfrac{9}{5} \cdot \bigg(\dfrac{9}{5}\bigg)^{12}\bigg]^{3} : \bigg(\dfrac{9}{5}\bigg)^{10} = \bigg[\bigg(\dfrac{9}{5}\bigg)^{1+12}\bigg]^{3} : \bigg(\dfrac{9}{5}\bigg)^{10} = \bigg[\bigg(\dfrac{9}{5}\bigg)^{13}\bigg]^{3} : \bigg(\dfrac{9}{5}\bigg)^{10} = \bigg(\dfrac{9}{5}\bigg)^{13 \cdot 3} : \bigg(\dfrac{9}{5}\bigg)^{10} = \bigg(\dfrac{9}{5}\bigg)^{39} : \bigg(\dfrac{9}{5}\bigg)^{10} = \bigg(\dfrac{9}{5}\bigg)^{39-10} = \bf \bigg(\dfrac{9}{5}\bigg)^{29}$