Question

10 Dacă a *a = 9, b = 3 x a, c = b × 6, calculează:
a+b+c= JO, b-a+c= T, 3 x a =
bx2 =​

Answer 1

Răspuns:

a·a=9=>a²=9=>a=√9=>a=3

b=3a=>b=3·3=>b=9

c=6b=>c=6·9=>c=54

a+b+c=3+9+54=>a+b+c=66

b-a+c=9-3+54=60

3a=3·3=9

2b=2·9=18