Question

10. Descompuneti in factori :
a)x^2-6x+8 b)x^2-4x+3 c)x^2-3x+2
d)x^2-7x+10 e)x^2-7x+6 f)x^2-8x+7
g)x^2-11x+28 h)x^2-9x+18 i)x^2-8x+15

Answer 1

Explicație pas cu pas:

a)x²-6x+8 = x²-2x-4x+8 = x(x-2)-4(x-2) =

= (x-2)(x-4)

b)x²-4x+3 = x²-x-3x+3 = x(x-1)-3(x-1) =

= (x-1)(x-3)

c)x²-3x+2 = x²-x-2x+3 = x(x-1)-2(x-1) =

= (x-1)(x-2)

d)x²-7x+10 = x²-2x-5x+10 = x(x-2)-5(x-2) =

= (x-2)(x-5)

e)x²-7x+6 = x²-x-6x+6 = x(x-1)-6(x-1) =

= (x-1)(x-6)

f)x²-8x+7 = x²-x-7x+7 = x(x-1)-7(x-1) =

= (x-1)(x-7)

g)x²-11x+28 = x²-4x-7x+28 = x(x-4)-7(x-4) =

= (x-4)(x-7)

h)x²-9x+18 = x²-3x-6x+18 = x(x-3)-6(x-3) =

= (x-3)(x-6)

i)x²-8x+15 = x²-3x-5x+15 = x(x-3)-5(x-3) =

= (x-3)(x-5)