Question

10. Rezolvaţi în R ecuațiile; a) 2x-√3 = 0; c)= √2x+3 = 11; e) √27x+1= √√3 x-4; g) 2√3x+2=√12x+2; 1) 0₂(3x+1,C b) 3x + √5 = 1; d) x-1 = √2x-√2; 1) 123-1-1 h) 3√2x-1=√18x+3.​

Answer 1

Răspuns:

a)2x-√3=0 c)√2x+3=11 =>2x=64=>x=64/2=>x=32

2x=√3 √2x=11-3

x=2√3 √2x=8=>2x=8^2=>

e)√27x+1=√3-4

3√3x-√3x=-4-1

2√3x=-5=>x=Ø(vida nu se poate)

g)2√3+2=√12x+2

2√3x=√12x|ridicam la putere a 2

4×3x=12x

12x=12x=>x € R=>x€(0,+infinit)

b)3x+√5=1

3x=1-√5

x=1-√5/3

d)x-1=√2x-√2

x-√2x=-√2-1

x=-1

h)3√2x-1=√18x+3

3√2x-1=3√2x+3

3√2x-3√2x=3-1=> x=Ø