Question

10 si 11, dau coroana​

Answer 1

Răspuns:

10) m(∡ACB)= 180°- ( 70°+60°)=50°⇒m(∡ACI)= m(∡ACB)/2=25°

     m(∡AIB)= 180°-(m∡ABI+m∡BAI)= 180°- ( 35°+30°)= 115°

11) m(∡CBD)+m(∡DCB)=180°-106°=74°⇒m(∡ABC)+m(∡ACB)=74°·2=148°⇒

m(∡A)= 180°-148°=32°

Explicație pas cu pas: