Question

10 supra 3x minus x supra 3 plus 5 supra x

Answer 1

$\frac{10}{3x} - \frac{x}{3} + \frac{5}{x} = \frac{10x}{3x} - \frac{x \times x}{x \times 3} + \frac{5}{x} = \frac{10x}{3x} - \frac{x \times x}{x \times 3} + \frac{3 \times 5}{3x} = \frac{10x}{3x} - \frac{ {x}^{2} }{x \times 3} + \frac{3 \times 5}{3x} = \frac{10x}{3x} - \frac{ {x}^{2} }{3x} + \frac{3 \times 5}{3x} = \frac{10x}{3x} - \frac{x {}^{2} }{3x} + \frac{15}{3x} = \frac{10 - x {}^{2} + 15}{3x} = \frac{25 - x {}^{2} }{3x}$

Answer 2

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