Question

10 supra √6 + 1 ,  -3 supa 1-√7  Ajuta-ma

Answer 1

$\frac{10}{ \sqrt{6}+1 } = \frac{10( \sqrt{6}-1) }{6-1} = \frac{10( \sqrt{6}-1) }{5} =2( \sqrt{6}-1)=2 \sqrt{6}-2$

$\frac{-3}{1- \sqrt{7} } = \frac{-3(1+ \sqrt{7}) }{1-7} = \frac{-3( 1+\sqrt{7} )}{-6} = \frac{1+ \sqrt{7} }{-2}$