Question

-10 supra x la a doua derivat?

Answer 1

$=- \frac{10' x^{2} -10( x^{2} )'}{( x^{2} )^2} =- \frac{0* x^{2} -20x}{x^4}= \frac{20x}{x^4}= \frac{20}{x^3}$