Question

10-(x -radical din 10) totul la a 2
5-(x-3 radical din 5 ) totl la a 2
(×- radical din) totul la a 2 -27
(× + 3 radical din 5 ) totul la a 2-20
(2×- radic din 11 ) totul la a 2
(×-8) totul la a 2 -(×-5) la a 2
DAU COROANA

Answer 1

10-(x -√10)²=(√10-x+√10)(√10+x-√10)=x(2√10-x)
5-(x-3√5 )²=(√5-x+3√5) (√5+x-3√5)=(4√5-x)(x-2√5)
(×- √3)² -27= (×- √3 -3√3)(×- √3 +3√3)= (×- 4√3)(× +2√3)
(× + 3√5)²-20= (× + 3√5-2√5)(× + 3√5+2√5)=(× + √5)(× + 5√5)
(2×- √11 )²=4ײ-4x√11+11
(×-8)² -(×-5)²= (×-8 -×+5) (×-8 +×-5)=(-3)(2×-13)=3(13-2×)
9 (x+2)² -4(x+5)²= [3(x+2) -2(x+5)][3(x+2) +2(x+5)]=
=(3x+6 -2x-10)(3x+6 +2x+10)=(x-4)(5x+16)