Question

100-[250-5×(c-5):5]×3=40
643-[(d-162):5+159]=454
[(3×e+4)×2+5]×3+5=170
VA ROG REPEDE DAU COROANA!!!

Answer 1

100-[250-5×(c-5):5]×3=40 
100 - (250-1(c-5))*30=40
100-(250-c+5)*30=40
100-(255-c)*30=40
100-(7650-30c)=40
100-7650 + 30c =40
-7550+30c=40
30c=40+7550
30c=7590 
c = 253

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643-[(d-162):5+159]=454
643 - (d-162/5 + 159)=454
643-d-162/5 - 159 = 454
484 - d-162/5 = 454
2420-d+162=2270
2582 - d = 2270
-d = 2270 - 2582
-d=-312
d = 312

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[(3×e+4)×2+5]×3+5=170
(6e+8+5)*3+5 = 170
(6e+13)*3+5=170
18e+39+5=170
18e+44=170
18e=170-44
18e=126
e = 7