Question

100-{62-3×[12:(5:5+3)+48:4-1]}×5+1=

Answer 1

100-{62-3×[12:(5:5+3)+48:4-1]}×5+1=1
5:5=1
1+3=4
12:4=3
48:4=12
3+12=15
15-1=14
3×14=42
62-42=20
20×5=100
100-100=0
0+1=1

Answer 2

100-{62-3×[12:(1+3)+48:4-1]}×5+1=
100-[62-3×(12:4+48:4-1)]×5+1=
100-[62-3×(3+12-1)]×5-1=
100-[62-3×(15-1)]×5-1=
100-(62-3×14)×5-1=
100-(62-42)×5-1=
100-20×5-1=
100-100-1=
0-1=
-1