Question

100 de balonase se impart la trei copii astfel: primii doi au 72, iar ultimii doi 59.Cate baloane are fiecare copil ?

Answer 1

$a+b+c=100$
$a+b=72$
$b+c=59$

$c=100-72=28$
$a=100-59=41$
$b=59-28=31$

Answer 2

x+y+z=100
x+y=72
y+z=59

z=100-72
z=28 baloane

x=100-59
x=41 baloane

y=100-28-41
y=31 baloane