Question

100IMULTIT[25-5IMULTIT(X-3)+2]:4=300

Answer 1

100*[25-5*(x-3)+2]:4 = 300

100*(25-5x+15+2):4 = 300

100*(42-5x):4 = 300

(4200 - 500x):4 = 300

1050 - 125x = 300

1050 - 300 = 125x

750 = 125x

x = 750/125

x = 6

Answer 2

100 ×  [ 25 - 5 × ( X - 3 ) + 2 ] : 4 = 300

100 ×  [ 25 - 5 × ( X - 3 ) + 2 ] = 300 × 4

100 ×  [ 25 - 5 × ( X - 3 ) + 2 ] = 1 200

25 - 5 × ( X - 3 ) + 2 = 1 200 : 100

25 - 5 × ( X - 3 ) + 2 = 12

25 - 5 × ( X - 3 )  = 12 - 2

5 × ( X - 3 ) = 25 - 10

5 × ( X - 3 )  = 15

X - 3 = 15 : 5

X - 3 = 3

X = 3 + 3

X = 6 → numarul, aflat prin metoda mersului invers