Question

105-{8+[3x(112-ax3:2-2)]}+1=38

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Answer 1

105-{8+[3×(112-a×3:2-2)]}+1=38

105-{8+[3×(112-3a:2-2)]}=38-1

105-{8+[3×(112-3a:2-2)]}=37

8+[3×(112-3a:2-2)]=105-37

8+[3×(112-3a:2-2)]=68

3×(112-3a:2-2)=68-8

3×(112-3a:2-2)=60

112-3a:2-2=60:3

112-3a:2-2=20

112-3a:2=20+2

112-3a:2=22

3a:2=112-22

3a:2=90

3a=90×2

3a=180

a=180:3

a=60