Question

10a -5*(a-b)*(a+b) daca a si b sunt nr consecutive iar a>b

Answer 1

a>b si a si b consecutive⇒a-b=1, a=b+1
a+b=b+1+b=2b+1
(a-b)(a+b)=1·(2b+1)=2b+1
10a-5(a-b)·(a+b)=10(b+1)-5(2b+1)=10b+10-10b-5=5