Question

10x{24*2:576+3x[(3*2x2)*15:(3*29x2*15)+1*21]}:13=
2*100x[2*50x2*48+(2*10x2*15)*5:2*27+(5*76:5*75-3)*90x2*8+2*98]=
[3*7x3*10+2*203:2*108-5:(5*2)*5]:(3*17+2*95-5*11)=


*=la puterea
X= inmultire

Answer 1

10×{576:576+3×[(3∧30×2∧15):(3∧29×2∧15)+1]}:13=
10×[1+3×(3+1)]:13=
10×(1+3×4):13=
10×13:13=
130:13=10
2∧100×[2∧98+(2∧50×2∧75):2∧27+(5-3)∧90×2∧8+2∧98]=
2∧100×[2∧98+2∧125:2∧27+2∧90×2∧8+2∧98]=
2∧100×(2∧98+298+2∧98+2∧98)=