Question

√11-6√2 ( primul radical acopera toata ecuatia la ambele ecuatii)
√21-8√5

Answer 1

$\sqrt{11 - 6 \sqrt{2} } = \sqrt{(3 - \sqrt{2} )^{2} } = 3 - \sqrt{2} \\ \sqrt{21 - 8 \sqrt{5}} = \sqrt{(4 - \sqrt{5})^{2} } = 4 - \sqrt{5}$
$Succese!$