Question

11 Calculați:
a √√324 (√49-√√25) + √256;
c √√84-√400+√150-√2500;
C
Rezolvare:
b √900: √225+√4 (√1225-√196)
d√√64+√4-√3-√729​

Answer 1

Explicație pas cu pas:

a)

$\sqrt{ \sqrt{324} } ( \sqrt{49} - \sqrt{ \sqrt{25} } ) + \sqrt{256} = 3 \sqrt{2}(7 - \sqrt{5}) + 16$

$\sqrt{324} ( \sqrt{49} - \sqrt{25}) + \sqrt{256} = 18(7 - 5) + 16 = 18 \times 2 + 16 = 36 + 16 = 52$

b)

$\sqrt{900} \div \sqrt{225} + \sqrt{4}( \sqrt{1225} - \sqrt{196}) = 30 \div 15 + 2(35 - 14) = 2 + 2 \times 21 = 2 + 42 = 44$

c)

$\sqrt{ \sqrt{84} } - \sqrt{400} + \sqrt{150} - \sqrt{2500} = \sqrt{2 \sqrt{21} } - 20 + 5 \sqrt{6} - 50 = \sqrt{2 \sqrt{21} } + 5 \sqrt{6} - 70$

d)

$\sqrt{ \sqrt{64} } + \sqrt{4} - \sqrt{3} - \sqrt{729} = \sqrt{8} + 2 - \sqrt{3} - 27 = 2 \sqrt{2} - \sqrt{3} - 25$