Question

11. Calculează, folosind relația √a· √b= √a·b sau relația √a: √b = √a: b: a) √2-√8; b) √10 √2 √5; c) √50: √2; d) √1000: √10; e) √65: √6³; f) √64: √2³:√2; g) √53: √√5; h) √18: √2; i) √√2-√√32. urgentt plss​

Answer 1

Explicație pas cu pas:

a)

$\sqrt{2} \times \sqrt{8} = \sqrt{2 \times 8} = \sqrt{16} = 4$

b)

$\sqrt{10} \times \sqrt{2} \times \sqrt{5} = \sqrt{10 \times 2 \times 5} = \sqrt{100} = 10$

c)

$\sqrt{50} \div \sqrt{2} = \sqrt{50 \div 2} = \sqrt{25} = 5$

d)

$\sqrt{1000} \div \sqrt{10} = \sqrt{1000 \div 10} = \sqrt{100} = 10$

e)

$\sqrt{ {6}^{5} } \div \sqrt{ {6}^{3} } = \sqrt{{6}^{5} \div {6}^{3}} = \sqrt{{6}^{2}} = 6$

f)

$\sqrt{64} \div \sqrt{ {2}^{3} } \div \sqrt{2} = \sqrt{ {2}^{6} \div {2}^{3} \div 2} = \sqrt{{2}^{3} \div 2} = \sqrt{{2}^{2}} = 2$

g)

$\sqrt{ {5}^{3} } \div \sqrt{5} = \sqrt{{5}^{3} \div 5} = \sqrt{ {5}^{2} } = 5$

h)

$\sqrt{18} \div \sqrt{2} = \sqrt{18 \div 2} = \sqrt{9} = 3$

i)

$\sqrt{2} \times \sqrt{32} = \sqrt{2 \times 32} = \sqrt{64} = 8$