Question

11. Fie triunghiul ABC. Aflati aria triunghiului, daca a) C) AB=10 cm, BC=12 cm, m(A)=90°​

Answer 1

$\it \Delta ABC-dreptunghic, \widehat A=90^o,\ \stackrel{T.P.}{\Longrightarrow } AC^2=BC^2-AB^2=12^2-10^2=\\ \\ =(12-10)(12+10)=2\cdot22=2\cdot2\cdot11=2^2\cdot11 \Rightarrow AC=2\sqrt{11} cm\\ \\ \mathcal{A}=\dfrac{c_1\cdot c_2}{2} =\dfrac{AB\cdot AC}{2}=\dfrac{10\cdot2\sqrt{11}}{2}=10\sqrt{11}\ cm^2$

Answer 2

Răspuns:

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