Question

(11 la puterea 2011×4 la puterea 1005) ÷[(22 la puterea 2 ) la 5] la puterea 201​ Repede dau coroana

Answer 1

Răspuns:   11

Explicație pas cu pas:

(11^2011 x 4^1005) : [(22^2)^5]^201 =

(11^2011 x (2^2)^1005) : [ (2^2 x 11^2)^5)]^201 =

(11^2011 x 2^2010) : [2^(2x5x201) x 11^(2x5x201)] =

(11^2011 x 2^2010) : [2^2010 x 11^2010] =

11^(2011-2010) x 2^(2010-2010) =

11^1 x 2^0 =

11 x 1 =

11  

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