Question

11 si 14 pls maxim stele si puncte de la 11a si 14 b

Answer 1

Explicație pas cu pas:

11.a)

$3 - \sqrt{11} = \sqrt{9} - \sqrt{11} < 0 \\ \implies |3 - \sqrt{11}| = \sqrt{11} - 3$

$4 - \sqrt{11} = \sqrt{16} - \sqrt{11} > 0 \\ \implies |4 - \sqrt{11}| = 4 - \sqrt{11}$

=>

$| - 3| + |3 - \sqrt{11} | + |4 - \sqrt{11} | = 3 + \sqrt{11} - 3 + 4 - \sqrt{11} = 4$

14.b)

$3 - \sqrt{7} = \sqrt{9} - \sqrt{7} > 0 \\ \implies |3 - \sqrt{7}| = 3 - \sqrt{7}$

$\sqrt{7} - 2 = \sqrt{7} - \sqrt{4} > 0 \\ \implies |\sqrt{7} - 2| = \sqrt{7} - 2$

$\sqrt{ {(3 - \sqrt{7} )}^{2} } + \sqrt{ {( \sqrt{7} - 2)}^{2} } = |3 - \sqrt{7} | + | \sqrt{7} - 2| = 3 - \sqrt{7} + \sqrt{7} - 2 = 1$