Question

111 in baza 2
11111 in baza 2

10101 in baza 2

Answer 1

Răspuns:

a)111(2)=1×2^2+1×2^1+1×2^0=

4+2+1=7(10)

b)11.111(2)=1×2^4+1×2^3+1×2^2+1×2^1+1×2^0=

16+8+4+2+1=31(10)

c)10101(2)=1×2^4+0×2^3+1×2^2+0×2^1+1×2^0=

16+0+4+0+1=21

Sper că te-am ajutat!