Question

(11supra6-1)+(3supra2-4supra6)=

Answer 1

$( \frac{11}{6}- \frac{6}{6})+( \frac{9}{6}- \frac{4}{6} )= \frac{5}{6} + \frac{5}{6}= \frac{10}{6}^{(2}=\boxed{ \frac{5}{3} }$