Question

12.046*10 la puterea 23 molecule de oxigen reactioneaza cu aluminiu.Se cere cantitatea in grame si in moli de AL2O3 care se obtine.

Answer 1

1mol O2..........6.022*10^23 molecule
x=2mol................12.046*10^23 molecule

4Al + 3O2 --> 2Al2O3

4 moli Al........3 moli O2......2 moli Al2O3
x=2.66 moli..2 moli............y=1.331 moli

MAl2O3=2AAl + 3AO=2*27+3*16=102g/mol

n=m/M==>m=n*M=1.331*102=135.762g Al2O3