Question

{12×20-[4×20+33-55+(12×10+6+306÷6-19]}÷3-23

Answer 1

{12×20-[4×20+33-55+(12×10+6+306÷6-19]}÷3-23 =
{240-[80+33-55+(120+6+51-19]}÷3-23
[240-(80+33-55+158)]÷3-23
(240-216)÷3-23=
24:3-23=
8-23=-15

Answer 2

{12×20-[4×20+33-55+(12×10+6+306÷6-19]}÷3-23 =

{240-[80+33-55+(120+6+51-19]}÷3-23 =

{240-[113-55+(126+51-19]}÷3-23 =

{240-[58+(177-19]}÷3-23 =

[240-(58+158]÷3-23 =

(240-216)÷3-23 =

24÷3-23 =

8 - 23 =

- 15