Question

Помогите пожалуйста,12 номер

Answer 1

6⁻¹⁰  /  81 ⁻² x 32⁻² =

3⁻¹⁰ x 2⁻¹⁰  / (3⁴)⁻² x (2⁵)⁻2 =

3⁻¹⁰ x 2⁻¹⁰ / 3⁻¹² x 2⁻¹⁰ =  ( se inverseaza fractiile )

3¹² x 2¹⁰ / 3¹⁰ x 2¹⁰ =

= 3⁽¹²⁻¹⁰⁾ =

3² = 9

(1/5)⁻²⁵  x 25⁻⁶  x 125 ⁻⁴ =

5²⁵ x (5²)⁻⁶ x (5³)⁻⁴ =

5²⁵ x 5⁻¹² x  5⁻¹²  =

5²⁵ x 1/5¹² x 1/5¹² =

5²⁵ / 5²⁴ =

5⁽²⁵⁻²⁴) =

5¹ =

5

(10⁻² - 1) ( 10 ⁻² + 1) =

(10⁻²)² - 1² =

10⁻⁴ - 1 =

1/10⁴ - 1 =

1/10000 -  1 =

-  9999/10000