Question

12. Determinati numerele A,B, şi C din tabelul de mai jos.A
B
94+x= 100
şi y: 17 = 6
A=43+ 3x + 3y
56 - 28 : (x+2) = 54
și (38 + y). 3 = 168
B = [152-5(x + y)]
28.(x+235) = 6860
şiy-37 = 13
C= 300 - (5y-3x)
7 ​

Answer 1

94+x=100

x=100-94

x=6

y:17=6

y=17*6

y=102

A=43+3x+3y=?

A=43+3*6+3*102

A=43+18+306

A=367

56-28:(x+2)=54

28:(x+2)=56-54

28:(x+2)=2

x+2=28:2

x+2=14

x=14-2

x=12

(38+y)*3=168

38+y=168:3

38+y=56

y=56-38

y=18

B=[152-5(x+y)]

B=[152-5(12+18)]

B=152-5*30

B=152-150

B=2

28*(x+235)=6860

x+235=6860:28

x+235=245

x=245-235

x=10

y-37=13

y=37+13

y=50

C=300-(5y-3x)

C=300-(5*50-3*10)

c=300-(250-30)

c=300-220

c=80