Question

12.Notand cu Mg media proportionala a numerelor a si b , aflati b stiind ca:
[tex]

[/tex]a) a=1 intreg 11/21 si Mg = 1 intreg 5/7
b) a=0.1 si mg 0.11
c) a=3.47(2) si Mg = 4,2(6)

Answer 1

a)a=32/21
Mg=√ab=12/7 =>√(32b/21)=12/7  l² 
=>32b/21=144/49 =>32b·49=21·144 =>b=(21·144)/(32·49)
=>b=27/14=1 intreg 13/14

b)a=1/10
Mg=√ab=11/100 =>√(b/10)=11/100  l²
=>b/10=121/10000 =>b=1210/10000 =>b=0,121

c)a=3 intregi (472-47)/900 = 3 intregi 425/900=3125/900=125/36
Mg=4 intregi (26-2)=4 intregi 24/90=384/90=64/15
√(125b/36)=64/15  l² =>125b/36=4096/225 
=>b=(36·4096)/(125·225) =>b=16384/3125 =>b=5,24288