Question

12/rad de ordin 3 din 4

Answer 1

$\frac{12}{ \sqrt[3]{4} } = \frac{12}{ \sqrt[3]{ {2}^{2} } } = \frac{12}{ {2}^{ \frac{2}{3} } } = \frac{ {2}^{2} \times 3}{ {2}^{ \frac{2}{3} } } = 3 \times {2}^{2 - \frac{2}{3} }$

$= 3 \times {2}^{ \frac{6}{3} - \frac{2}{3} } = 3 \times {2}^{ \frac{4}{3} }$