Question

12 radical din 2-12 radical din 3-30 radical din 2+36 radical din 3

Answer 1

$12 \sqrt{2}-12 \sqrt{3} -30 \sqrt{2} +36 \sqrt{3} = \\ \\ 12 \sqrt{2}-30 \sqrt{2} +36 \sqrt{3} -12 \sqrt{3} = \\ \\ 24 \sqrt{3} -18 \sqrt{2} = \\ \\ =6(4 \sqrt{3} -3 \sqrt{2} ) \\ \\ 12 \sqrt{2}-12 \sqrt{3} -30 \sqrt{2} +36 \sqrt{3} =6(4 \sqrt{3} -3 \sqrt{2} )$