Question

√12 x (√108 - 2√48)- √18 x (√288 - √72)

Answer 1

√12 x (√108 - 2√48)- √18 x (√288 - √72) = 2√3*(6√3 -  8√3)- 3√2(12√2-6√2)=

=2√3*(-2√3)- 3√2*6√2= -12 - 36= -48

Answer 2

[tex]descompun\;numerele\;de\;sub\;radical\;...\\ =\sqrtaa{4*3}*(\sqrt{36*3}-2\sqrt{16*3})-\sqrt{9*2}*(\sqrt{144*2}-\sqrt{36*2})=\\ =2\sqrt3*(6\sqrt3-8\sqrt3)-3\sqrt2(12\sqrt2-6\sqrt2)=\\ =2 \sqrt{3} *(-2 \sqrt{3})\,-\,3 \sqrt{2} *6 \sqrt{2} =\\ =\;-4*3\;-\;18*2=\;-12\;-\;36=\;-\;48[/tex]