Question

120 g de naoh a reactionat cu acidul azotic (HNO3). Calculati masa sarii (azotatului de sodiu)Na2SO4

Answer 1

Răspuns:

Explicație:

120g NaOH

react. cu HNO3

masa de sare form.

120g                       xg

NaOH  + HNO3= NaNO3 + H2O

40g                         85g

x= 120. 85 : 40=255g NaNO3

n= 255g : 85g/moli= 3 moli NaNO3

MNaOH=23 + 16 +1=40------> 40g/moli

MNaNO3=23 + 14 + 3.16=85------> 85g/moli

Answer 2

Răspuns:

120g NaOH react. cu HNO3 masa de sare form.

120g xg

NaOH + HNO3= NaNO3 + H2O

40g 85g

x= 120. 85 : 40=255g NaNO3

n= 255g : 85g/moli= 3 moli NaNO3

MNaOH=23 + 16 +1=40------> 40g/moli

MNaNO3=23 + 14 + 3.16=85------> 85g/moli