Question

1200-(2y+100):19+2500=3500

Answer 1

1200-(2y+100):19+2500=3500
1200-(2y+100):19= 3500-2500
1200-(2y+100):19= 1000
(2y+100):19= 1200-1000
(2y+100):19= 200
(2y+100)= 200×19
2y+100= 3800
2y= 3800-100
2y= 3700
y= 3700/2
y= 1850

Answer 2

Răspuns

Explicație pas cu pas:

1 200 - ( 2 y + 100 ) : 19 + 2 500 = 3 500

1 200 - ( 2 y + 100 ) : 19 = 3 500 - 2 500

1 200 - ( 2 y + 100 ) : 19 = 1 000

( 2 y + 100 ) : 19 = 1 200 - 1 000

( 2 y + 100 ) : 19 = 200

2 y + 100 = 200 × 19

2 y + 100 = 3 800

2 y = 3 800 - 100

2 y = 3 700

y = 3 700 : 2

y = 1 850 → numarul, aflat prin metoda mersului invers