Question

1200+4{5+2x[3x(a-2)+12]:7-2}:3=2012 va rog repede dau multe puncte

Answer 1

Răspuns: $\purple{\underline{\bf~ a=705~}}$

Explicație pas cu pas:

$\bf 1200+ 4\cdot \big\{5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2\big\}:3=2012$

$\bf 4\cdot \big\{5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2\big\}:3=2012-1200$

$\bf 4\cdot \big\{5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2\big\}:3=812~~~\bigg|\cdot 3$

$\bf 4\cdot \big\{5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2\big\}=812\cdot 3~~~\bigg|:4$

$\bf \big\{5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2\big\}=812\cdot 3:4$

$\bf 5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2=203\cdot 3$

$\bf 5+2\cdot\big[3\cdot(a-2)+12\big ]:7-2=609$

$\bf 5+2\cdot\big[3\cdot(a-2)+12\big ]:7=609+2$

$\bf 2\cdot\big[3\cdot(a-2)+12\big ]:7=611-5$

$\bf 2\cdot\big[3\cdot(a-2)+12\big ]:7=606~~~\bigg|\cdot 7$

$\bf 2\cdot\big[3\cdot(a-2)+12\big ]=606\cdot 7~~~\bigg|:2$

$\bf \big[3\cdot(a-2)+12\big ]=606\cdot 7:2$

$\bf \big[3\cdot(a-2)+12\big ]=303\cdot 7$

$\bf 3\cdot(a-2)+12=2121$

$\bf 3\cdot(a-2)=2121-12$

$\bf 3\cdot(a-2)=2109~~~\bigg|:3$

$\bf a-2=703$

$\bf a=703+2$

$\red{\underline{\bf~ a=705~}}$