Question

122 - 12 • {183:[(2•3³•5³)⁴:(2⁴•3⁷•5¹²)+(2⁸)⁹:16¹⁸-1²⁷•5⁰]-3²•(54-2⁴•3)}
REPEDE VA ROGG DAU COROANA​

Answer 1

Răspuns:

Explicație pas cu pas:

$122-12 \cdot \{183:[(2\cdot3^3\cdot5^3)^4:(2^4\cdot3^7\cdot5^{12})+(2^8)^9:16^{18}-1^{27}\cdot5^0]-3^2\cdot(54-2^4\cdot3)\}=$

$122-12 \cdot \{183:[(2^4\cdot3^7\cdot5^{12}):(2^4\cdot3^7\cdot5^{12})+(2^8)^9:16^{18}-1\cdot1]-3^2\cdot(54-2^4\cdot3)\}=$

$122-12 \cdot \{183:[1+(2^8)^9:16^{18}-1\cdot1]-3^2\cdot(54-2^4\cdot3)\}=$

$122-12 \cdot \{183:[1+2^{8\cdot9}:(2^{4})^{18}-1\cdot1]-3^2\cdot(54-16\cdot3)\}=$

$122-12 \cdot [183:(1+2^{72}:2^{4\cdot18}-1)-3^2\cdot(54-48)]=$

$122-12 \cdot [183:(1+2^{72}:2^{72}-1)-3^2\cdot 6]=$

$122-12 \cdot [183:(1+2^{72-72}-1)-3^2\cdot 6]=$

$122-12 \cdot [183:(1+2^{0}-1)-9\cdot 6]=$

$122-12 \cdot [183:(1+1-1)-54]=$

$122-12 \cdot (183:1-54)=$

$122-12 \cdot (183-54)=$

$122-12 \cdot 129=$

$122-1548=$

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