Question

124 impartit la 1 la puterea 115 totul la puterea 2 minus 0 la puterea 21 totul la puterea 10 ori 2 la puterea 350​

Answer 1

Rezolvarea este in poza

Answer 2

Răspuns:

[(124:$1^{115}$$)^{2}$-$0^{21}$$]^{10}$x$2^{350}$=

[(124:1$)^{2}$-0$]^{10}$x$2^{350}$=

($124^{2}$$)^{10}$x$2^{350}$=

$124^{20}$x$2^{350}$=

$124^{20}$x$124^{2}$=$124^{22}$