Question

126-((63*2/6+109)*(75/25+21/3))/10

deci o suta minus paranteza dreapta paranteza rotunda saizeci si trei ori doi impartit la sase plus o suta noua paranteza rotunda inchisa ori paranteza rotunda deschisa saptezeci si cinci impartit la douazaci si cinci plus douazeci si unu impartit la trei paranteza rotunda inchisa si paranteza dreapta impartit la zece

va rog frumos ajutatima repede


am scris acolo ce trebuie sa calculati sper ca ati inteles

Answer 1

126-[(63*2/6+109)*(75/25+21/3)]/10=
=126-[(126/6+109)*(3+7)]/10=
=126-[(21+109)*10]/10=
=126-(130*10)/10=
=126-130=-4

Answer 2

126 - [(63x2:6+109)x(75:25+21:3)] :10=
126- [(21+109)x(3+7)]:10=
126-[130x10]:10=
126- 1300:10 =
126-130= -4