Question

12supra radical de ordinul 3 din 4

Answer 1

3*4/∛4=(3∛4³)/∛4= 3∛4²=3∛16

Answer 2

$\frac{12}{ \sqrt[3]{4} } = \frac{12 \sqrt[3]{4} * \sqrt[3]{4} }{4}=3 \sqrt[3]{16}=3 \sqrt[3]{8*2}=6 \sqrt[3]{2}$