Question

13 repede va rog dau coroana !

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

a)

$\sqrt{2^{2}+\dfrac{5^{2} \cdot3^{2}}{4^{2}}}=\sqrt{25+\dfrac{25\cdot9}{16}}=\sqrt\dfrac{25\cdot16+225}{16}}=\dfrac{\sqrt{625}}{\sqrt{16}}=\boxed{\dfrac{25}{4}}$

b)

$\sqrt{3^{2}+\dfrac{3^{4}}{2^{4}}}=\sqrt{\dfrac{16\cdot9+81}{16}}=\sqrt\dfrac{144+81}{16}}=\dfrac{\sqrt{225}}{\sqrt{16}}=\boxed{\dfrac{15}{4}}$

c)

$\sqrt{7^{2}+\dfrac{7^{2}\cdot4^{2}}{9}}=\sqrt{\dfrac{49\cdot9+49\cdot16}{16}}=\sqrt{\dfrac{1225}{9}}=\boxed{\dfrac{35}{3} }$

d)

$\sqrt{4^{2}+\dfrac{4^{2}\cdot5^{2}}{12^{2}}}=\sqrt{\dfrac{16\cdot144+16\cdot25}{144}}=\sqrt{\dfrac{2304+400}{144}}=\sqrt{\dfrac{2704}{144}}=\boxed{\dfrac{13}{3} }$

e)

$\sqrt{\dfrac{3^{2}\cdot13^{2}}{5^{2}}-3^{2}}=\sqrt{\dfrac{9\cdot169-25\cdot9}{25}}=\sqrt{\dfrac{1521-225}{25}}=\sqrt\dfrac{1296}{25}}= \boxed{\dfrac{36}{5} }$

f)

$\sqrt{\dfrac{5^{2}\cdot8^{2}}{3^{2}}+5^{2}\cdot 2^{2}}=\sqrt{\dfrac{25\cdot64+25\cdot4\cdot9}{9}} =\sqrt{\dfrac{1600+900}{9}}=\sqrt{\dfrac{2500}{9}}=\boxed{\dfrac{50}{3} }$

g)

$\sqrt{\dfrac{7^{2}\cdot8^{2}}{15^{2}}+7^{2} }=\sqrt{\dfrac{49\cdot64+49\cdot225}{225}}=\sqrt{\dfrac{3136+11025}{225}}=\sqrt{\dfrac{14161}{225}}=\boxed{\dfrac{119}{15} }$