Question

13 va rog..............

Answer 1

0,08(3)=1/12

0,0(6)=1/15

           M

  D.................C

A......M'........C'........B

CC'/12=BC/15⇒CC'=12K;BC=15K

AC=BD=40

BC'=√(15K)²-12K²=9K⇒BC²=BC'×AB⇒AB=225K²/9K=25K

CD=C'D'=25K-2×9K=7K

T.Pitagora ΔACB⇒AC=40=√AB²-BC²=20 K⇒K=AC/20=2

a)AB=25×2=50

CD=7×2=14

CC'=12×2=24 h

b)Aria=(AB+CD)×CC'/2

c)ΔMM'C≈ΔMM'B