Question

1300-3x{11x[4x10-5x(6xa-10)]+70}=100
Vreau rezolvarea

Answer 1

Răspuns:

Explicație pas cu pas:

-3x{ 11x [ 4x10 -5x ( 6xa -10)]+70} = 1300-100

-3x{ 11x [ 4x10-5x(6xa -10)]+70}=1.200

11x{[ 4x10 -5x ( 6xa-10 )]+70} =1200 :3

11x [ 4x10-5x(6xa-10)] =400 -70

11x[4x10-5x(6xa-10)]=330

4x10-5x(6xa-10)=330:11

4x10-5x(6xa-10)= 30

40-5x(6xa-10)=30

40-30=5x(6xa-10)

10=5x(6xa-10)

5x( 6a-10)=10

6xa-10=10:5

6xa-10=2

6xa=2+10

6xa=12

a= 12:6

a= 2