Question

[136+(42×a×8-905)-27×80]÷5=19

Answer 1

1 Simplify brackets.

\frac{136+42a\times 8-905-27\times 80}{5}=19

5

136+42a×8−905−27×80

=19

2 Simplify 42a\times 842a×8 to 336a336a.

\frac{136+336a-905-27\times 80}{5}=19

5

136+336a−905−27×80

=19

3 Simplify 27\times 8027×80 to 21602160.

\frac{136+336a-905-2160}{5}=19

5

136+336a−905−2160

=19

4 Simplify 136+336a-905-2160136+336a−905−2160 to 336a-2929336a−2929.

\frac{336a-2929}{5}=19

5

336a−2929

=19

5 Multiply both sides by 55.

336a-2929=19\times 5336a−2929=19×5

6 Simplify 19\times 519×5 to 9595.

336a-2929=95336a−2929=95

7 Add 29292929 to both sides.

336a=95+2929336a=95+2929

8 Simplify 95+292995+2929 to 30243024.

336a=3024336a=3024

9 Divide both sides by 336336.

a=\frac{3024}{336}a=

336

3024

10 Simplify \frac{3024}{336}

336

3024

to 99.

a=9a=9