Question

√ 144 supra √ 16 = 2 + x supra √ 9​

Answer 1

$\frac{\sqrt{144} }{\sqrt{16} } = {\frac{2+x}{\sqrt{9} } }$

$\frac{2+x}{\sqrt{9}}=\frac{\sqrt{144}}{\sqrt{16}}$

$\sqrt{144} =\sqrt{2^4\cdot \:3^2} =\sqrt{2^4}\sqrt{3^2}$

$\sqrt{16} = \sqrt{2^4}$

$\frac{\sqrt{2^4}\sqrt{3^2}}{\sqrt{2^4}} =$

$\frac{2+x}{\sqrt{9}}=\sqrt{3^2}$

$\frac{3\left(2+x\right)}{\sqrt{9}}=3\cdot \:3$

$2+x=9$

$x=7$

Answer 2

Răspuns:

Explicație pas cu pas: