Question

15^2-5•[(5^7)^8:5^30+5•5^21-5^26]:25^10

Answer 1

${15}^{2} - 5 \times ( {( {5}^{7})}^{8} \div {5}^{30} + 5 \times {5}^{21} - {5}^{26} ) \div {25}^{10} = \\ = 225 - 5 \times ( {5}^{7 \times 8} \div {5}^{30} + {5}^{21 + 1} - {5}^{26} ) \div { ({5}^{2}) }^{10} \\ = 225 - 5 \times ( {5}^{56} \div {5}^{30} + {5}^{22} - {5}^{26} ) \div {5}^{2 \times 10} \\ = 225 - 5 \times ( {5}^{26} + {5}^{22} - {5}^{26} ) \div {5}^{20} \\ = 225 - 5 \times {5}^{22} \div {5}^{20} \\ = 225 - 5 \times {5}^{2} \\ = 225 - 5 \times 25 \\ = 225 - 125 \\ = 100$

Answer 2

Răspuns

Explicație pas cu pas:

15² - 5 x [ ( 5⁷ )⁸ : 5³⁰ + 5 x 5²¹ - 5²⁶ ] : 25¹⁰ = 100

= 225 - 5 x ( 5⁷ˣ⁸ : 5³⁰ + 5⁽ ¹ ⁺ ²¹ ⁾ - 5²⁶ ) : ( 5² )¹⁰ =

= 225 - 5 x ( 5⁽ ⁵⁶ ⁻ ³⁰ ⁾ + 5²² - 5²⁶ ) : 5²ˣ¹⁰ =

= 225 - 5 x ( 5²⁶ + 5²² - 5²⁶ ) : 5²⁰ =

= 225 - 5 x 5²² : 5²⁰ =

= 225 - 5 ⁽ ¹ ⁺ ²² ⁻ ²⁰ ⁾ =

= 225 - 5³ =

= 225 - 125 =

= 100